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##### PHYSICS (2016) QUIZ STUDY

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Which of the above forms of energy can directly be converted to light energy?

= 10

^{o}C to 10

^{o}C. Calculate the decrease in the length of the wire. [c = 3 x 10

^{-5}K

^{-1}]

^{-4}m

^{-4}m

^{-3}m

^{-3}m

**NOT**correct?

^{-2}vertically upwards?

[g = 10ms

^{-2}

10 x 30 = 15 x X

X = 20cm

^{-1}at an angle of a 30

^{o}to the horizontal.

Calculate the time taken to reach the maximum height?

[g = 10ms

^{-2}]

^{-1}is subjected to a uniform deceleration of 2ms

^{-2}. The time required to bring the train to a complete halt is

= 10s

^{-6}s

^{-1}.

Calculate its half - life?

^{6}s

^{7}s

^{9}s

^{7}s

_{1/2}= \(\frac{0.693}{\gamma}\) = \(\frac{0.693}{10^-6}\)

= 6.93 x 10

^{7}

^{6}Nm

^{-2}with a volume of 10

^{-3}m

^{3}.

[R = 8.3jmol

^{-1}K

^{-1}]

^{o}C

^{o}C

^{o}C

^{o}C

= 153

^{o}C

^{o}C?

[Refractive index of water = 1.33]

Rd = 1.33 x 1 = 1.330m

= 3.7 x 10 = 37N

The impulse of a force is deduced from Newton's second law as

F = ma

F = m( \(\frac{v - u}{t}\))

F = mg

F = mv - mu

If the magnification of a virtual image formed by an object 10cm from a convex less is 3, then the focal length of the lens is

10cm

20cm

25cm

15cm

M = \(\frac{v}{u}\) = 3 = \(\frac{v}{30}\). V = 30m

\(\frac{1}{u}\) + \(\frac{1}{v}\) = \(\frac{1}{f}\) = \(\frac{1}{10}\) - \(\frac{1}{30}\) = \(\frac{1}{f}\)

\(\frac{3 - 1}{30}\) = \(\frac{1}{f}\)

f = \(\frac{30}{2}\) = 15cm

[h = 6.6 x 10

^{-34}Js; f = 10

^{15}Hz]

= 1.51eV

In the diagram above, which of the following velocity-time graphs shows uniform acceleration of a body from rest?

C

D

B

A

In the diagram above, the neutral point is at

R

X

S

P

From the diagram above, the measuring accuracy of the micrometer screw gauge is

4.78mm

4.16mm

4.66mm

4.70mm

In the diagram above, the direction of the force between N and S in the magnetic field is

MP

SN

NS

PM

_{2}- f

_{1}= 270 - 258 = 12Hz